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Conic Sections

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

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Reading time~8 min
Revision time~3 min
Last updated2026-07-17
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🎯 Key Points

  • Eccentricity sorts all conics on one scale: e=0 (circle) → 0<e<1 (ellipse) → e=1 (parabola) → e>1 (hyperbola)
  • Ellipse: c²=a²-b² (foci INSIDE the curve, sum of focal distances=2a constant); Hyperbola: c²=a²+b² (foci OUTSIDE relative to vertices, DIFFERENCE of focal distances=2a constant) — opposite sign in the c² relation is the key distinguishing feature
  • Parabola y²=4ax: focus (a,0), directrix x=-a, latus rectum length 4a — latus rectum is the focal chord PERPENDICULAR to the axis
  • For an ellipse x²/a²+y²/b²=1, the LARGER denominator tells you which axis is the major axis — don't assume x² always goes with the major axis
The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Conic Sections

A conic section is the curve obtained when a plane intersects a double-napped right circular cone. Depending on the angle of the cutting plane relative to the axis of the cone, the resulting curve is a circle, parabola, ellipse, or hyperbola. These curves can also be defined as the locus of a point whose distance from a fixed point (focus) bears a constant ratio (eccentricity) to its distance from a fixed line (directrix).

Circle (Quick Recap)

  • A circle is the set of points equidistant from a fixed point (center).
  • Standard equation with center (h, k) and radius r: (x - h)² + (y - k)² = r²
  • Center at origin: x² + y² = r²
  • General form: x² + y² + 2gx + 2fy + c = 0, with center (-g, -f) and radius √(g² + f² - c)
  • A circle is a special conic with eccentricity e = 0.

Parabola

  • A parabola is the locus of a point that moves so that its distance from a fixed point (focus) equals its distance from a fixed line (directrix). Eccentricity e = 1.
  • Standard equation: y² = 4ax (opens rightward, a > 0)
  • Focus: (a, 0)   Directrix: x = -a   Vertex: (0, 0)   Axis: x-axis
  • Latus rectum (the focal chord perpendicular to the axis) has length 4a, with endpoints (a, 2a) and (a, -2a).
  • Parametric form: x = at², y = 2at
  • Other orientations: y² = -4ax (opens left), x² = 4ay (opens up), x² = -4ay (opens down), each with focus and directrix adjusted accordingly.

Ellipse

  • An ellipse is the locus of a point such that the sum of its distances from two fixed points (foci) is constant. Eccentricity 0 < e < 1.
  • Standard equation: x²/a² + y²/b² = 1, with a > b > 0 (major axis along x-axis)
  • Relationship between a, b, c: c² = a² - b², where c is the distance from center to each focus.
  • Foci: (±c, 0)   Vertices: (±a, 0)   Eccentricity: e = c/a
  • Directrices: x = ±a/e
  • Latus rectum length: 2b²/a
  • Length of major axis = 2a, length of minor axis = 2b
  • When the major axis is along the y-axis (b > a in the equation form x²/b² + y²/a² = 1 with a > b), foci are (0, ±c) and the roles of axes swap.
  • Sum of focal distances from any point on the ellipse to the two foci = 2a (constant).

Hyperbola

  • A hyperbola is the locus of a point such that the absolute difference of its distances from two fixed points (foci) is constant. Eccentricity e > 1.
  • Standard equation: x²/a² - y²/b² = 1 (transverse axis along x-axis)
  • Relationship between a, b, c: c² = a² + b², where c is the distance from center to each focus.
  • Foci: (±c, 0)   Vertices: (±a, 0)   Eccentricity: e = c/a (always > 1)
  • Latus rectum length: 2b²/a
  • Asymptotes: y = ±(b/a)x, lines that the hyperbola approaches but never touches as it extends to infinity
  • Difference of focal distances from any point on the hyperbola to the two foci = 2a (constant, in absolute value).

Comparison of Conics by Eccentricity

ConicEccentricity (e)Shape
Circlee = 0Perfectly round, both foci coincide at center
Ellipse0 < e < 1Oval, two distinct foci inside the curve
Parabolae = 1Open curve, one focus and one directrix
Hyperbolae > 1Two separate open branches, asymptotic lines

Key Tips for Problem Solving

  • To identify a conic from its general equation, compare coefficients with the standard forms after shifting/rotating if needed.
  • Always check whether the major axis is along the x-axis or y-axis by comparing the denominators under x² and y² in the ellipse equation (larger denominator indicates the axis direction).
  • For a hyperbola, b is not necessarily less than a; only the relation c² = a² + b² matters since c > a always.

🚀 JEE Advanced Edge

Why the focal-distance-sum/difference properties are the "real" definitions: The focus-directrix definition (distance to focus = e × distance to directrix) and the focal-distance-sum/difference definition are EQUIVALENT for each conic, but the sum/difference form (2a constant) is usually faster for proving locus problems, since it avoids setting up a directrix line at all — recognizing which definition to invoke saves significant algebra in JEE-level locus questions.

Rectangular hyperbola as a special case: When a=b in x²/a²-y²/b²=1, the hyperbola becomes "rectangular" (asymptotes y=±x are perpendicular), and its eccentricity is always e=√2 regardless of the value of a — a useful shortcut when a problem states "rectangular hyperbola" without giving explicit asymptote directions.

Worked problem: Find the eccentricity of the ellipse 4x²+9y²=36. Approach: Divide by 36: x²/9+y²/4=1, so a²=9, b²=4 (a²>b², major axis along x). c²=a²-b²=9-4=5, so c=√5. Eccentricity e=c/a=√5/3.

Worked Example: Parabola — Focus, Directrix, Length of Latus Rectum

For the parabola y² = 12x, find the focus, equation of the directrix, and length of the latus rectum.

Compare with y² = 4ax: 4a = 12 → a = 3. Focus = (a, 0) = (3, 0). Directrix: x = −a → x = −3. Length of latus rectum = 4a = 12.

Worked Example: Equation of a Circle

Find the equation of the circle passing through (1, 0), (−1, 0), and (0, 1).

General form: x² + y² + Dx + Ey + F = 0. Substituting (1,0): 1 + D + F = 0. (−1,0): 1 − D + F = 0. Subtracting: 2D = 0 → D = 0, F = −1. (0,1): 1 + E − 1 = 0 → E = 0. Equation: x² + y² = 1 (unit circle centred at origin). Three points determine a unique circle.

2 Revise ~3 min before the exam

📐 Formula Sheet

  • Circle: (x − h)² + (y − k)² = r²  |  general x² + y² + 2gx + 2fy + c = 0, centre (−g, −f), radius √(g² + f² − c)
  • Parabola y² = 4ax: vertex (0,0), focus (a,0), directrix x = −a, latus rectum 4a
  • Ellipse x²/a² + y²/b² = 1 (a > b): foci (±ae, 0), e = √(1 − b²/a²), latus rectum 2b²/a
  • Hyperbola x²/a² − y²/b² = 1: foci (±ae, 0), e = √(1 + b²/a²), asymptotes y = ±(b/a)x
  • Eccentricity: circle 0, parabola 1, ellipse < 1, hyperbola > 1
  • Focal distances — ellipse: sum = 2a  |  hyperbola: difference = 2a
  • Tangent to y² = 4ax at (x₁, y₁): yy₁ = 2a(x + x₁)
  • Condition for tangency: y = mx + c touches y² = 4ax when c = a/m
3 Practice apply it

✍️ Worked Examples

Example 1 — Centre and radius of a circle
Q: Find the centre and radius of x² + y² − 6x + 4y − 12 = 0.
Step 1 — Compare with x² + y² + 2gx + 2fy + c = 0: 2g = −6 ⇒ g = −3; 2f = 4 ⇒ f = 2; c = −12.
Step 2 — Centre is (−g, −f): (3, −2).
Step 3 — Radius: √(g² + f² − c) = √(9 + 4 + 12) = √25 = 5.
Answer: centre (3, −2), radius 5. Trap: the centre signs flip — g = −3 gives centre x = +3.

Example 2 — Properties of a parabola
Q: For y² = 12x, find the focus, directrix and length of the latus rectum.
Step 1 — Compare with y² = 4ax: 4a = 12 ⇒ a = 3.
Step 2 — Focus is (a, 0): (3, 0). Directrix is x = −a: x = −3.
Step 3 — Latus rectum = 4a: 12.
Answer: focus (3,0), directrix x = −3, latus rectum 12. Note: the parabola opens rightward because a > 0.

Example 3 — Eccentricity of an ellipse
Q: Find the eccentricity and foci of x²/25 + y²/16 = 1.
Step 1 — Read off: a² = 25 ⇒ a = 5; b² = 16 ⇒ b = 4. Since a > b, the major axis is horizontal.
Step 2 — Eccentricity: e = √(1 − b²/a²) = √(1 − 16/25) = √(9/25) = 3/5.
Step 3 — Foci at (±ae, 0): ae = 5 × 3/5 = 3.
Answer: e = 0.6, foci (±3, 0). Sense check: e < 1 for every ellipse ✓.

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Frequently Asked Questions — Conic Sections

What are the key concepts in Conic Sections?
Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.
Is Conic Sections important for JEE?
Yes. Conic Sections is part of the Mathematics Class 11 NCERT syllabus and is directly tested in JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Conic Sections questions on StudyHub?
Open StudyHub and select Mathematics → Conic Sections. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at JEE level with full step-by-step explanations.

References

  1. NCERT Class 11 Mathematics Textbook — Chapter: Conic Sections
  2. CBSE Curriculum — Mathematics (Class 11)
  3. NTA JEE Main Official Syllabus — subject-wise topic list