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Matrices

Matrix operations, determinants, inverses, and solving linear systems

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Last updated2026-07-17
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🎯 Key Points

  • Matrix multiplication requires columns of A = rows of B; (AB)≠(BA) in general (NOT commutative) — order matters, unlike scalar multiplication
  • A⁻¹=adj(A)/det(A) exists ONLY when det(A)≠0 (non-singular); a matrix with det=0 (singular) has NO inverse
  • System AX=B: if det(A)≠0, unique solution X=A⁻¹B; if det(A)=0, either NO solution or INFINITELY many — never "exactly one" in the singular case
  • Symmetric: A=Aᵗ (mirror across diagonal); Skew-symmetric: A=-Aᵗ (diagonal entries must be 0, since aᵢᵢ=-aᵢᵢ forces aᵢᵢ=0)

Matrices & Determinants

Matrix A (3 rows x 3 columns)a11a12a13a21a22a23a31a32a33column 1column 2column 3row 1row 2row 3

Element aij of matrix A sits at the intersection of row i and column j.

A matrix is a rectangular arrangement of numbers in rows and columns. Matrices are used to represent and solve systems of linear equations and have broad applications in science and engineering.

Types of Matrices

  • Row matrix: Only one row
  • Column matrix: Only one column
  • Square matrix: Equal rows and columns
  • Diagonal matrix: Non-zero entries only on main diagonal
  • Identity matrix (I): Diagonal with all 1s; AI = IA = A
  • Zero matrix: All entries are 0
  • Symmetric: A = A^T  |  Skew-symmetric: A = -A^T

Matrix Operations

unit square->transformed parallelogramMatrix [[2,1],[0,1]] maps (1,0) to (2,0) and (0,1) to (1,1)

A matrix transforms the unit square into a parallelogram by mapping its corner vectors to new positions.

  • Addition: Element-wise; matrices must have the same order
  • Scalar multiplication: kA multiplies every element by k
  • Matrix multiplication: (AB)_ij = row i of A dotted with column j of B; columns of A must equal rows of B
  • Transpose (A^T): Rows become columns. (AB)^T = B^T A^T

Determinants

  • 2x2: det [[a,b],[c,d]] = ad - bc
  • 3x3: Expand along any row/column using cofactors with alternating signs
  • det(AB) = det(A) det(B); det(A^T) = det(A); det(kA) = k^n det(A)
  • Row of zeros or two identical rows means det = 0

Inverse of a Matrix

A^(-1) = adj(A) / det(A). Exists only when det(A) is not 0.

  • Adjoint adj(A): Transpose of the cofactor matrix

System of Linear Equations

  • Matrix method: AX = B → X = A^(-1)B when det(A) is not 0
  • Cramer's rule: x_i = det(A_i) / det(A)
  • Singular (det = 0): either no solution or infinitely many

Cayley-Hamilton Theorem

Every square matrix satisfies its own characteristic polynomial p(lambda) = 0, so p(A) = 0. Used to find powers and inverse of A.

Algebra of Matrices: Properties

  • Addition (same order only) is commutative A+B=B+A and associative (A+B)+C=A+(B+C); the zero matrix O is the additive identity and −A is the additive inverse.
  • Scalar multiplication distributes: k(A+B)=kA+kB and (k+l)A=kA+lA.
  • Matrix multiplication is associative (AB)C=A(BC) and distributive A(B+C)=AB+AC, but is NOT commutative in general (AB≠BA); also AB=O does not imply A=O or B=O.
  • With a conformable identity matrix, IA=AI=A.

Properties of Transpose

  • (A^T)^T = A
  • (A+B)^T = A^T + B^T
  • (kA)^T = kA^T
  • (AB)^T = B^T A^T — note the reversed order (reversal law)

Symmetric and Skew-Symmetric Decomposition

  • Symmetric: A = A^T (aij = aji). Skew-symmetric: A = −A^T (aij = −aji), which forces every diagonal entry to be 0.
  • Theorem: every square matrix can be written uniquely as the sum of a symmetric and a skew-symmetric matrix.
  • A = ½(A + A^T) + ½(A − A^T), where ½(A + A^T) is symmetric and ½(A − A^T) is skew-symmetric.

Elementary Operations and Inverse by Elementary Transformations

  • Three elementary row (or column) operations: interchange two rows (Ri↔Rj), multiply a row by a non-zero scalar (Ri→kRi), or add a multiple of one row to another (Ri→Ri+kRj).
  • To find A⁻¹ by row operations, write A = IA, then reduce the left matrix A to I using row operations applied to both sides; I is transformed into A⁻¹.
  • If, during the reduction, an entire row of the left matrix becomes zero, then A is singular and A⁻¹ does not exist.

Invertible Matrices and Uniqueness of Inverse

  • A square matrix A is invertible if there exists B with AB = BA = I; then B = A⁻¹.
  • The inverse is unique: if B and C are both inverses, then B = BI = B(AC) = (BA)C = IC = C.
  • A is invertible ⟺ det(A) ≠ 0 (non-singular).
  • Reversal law: (AB)⁻¹ = B⁻¹A⁻¹, and (A^T)⁻¹ = (A⁻¹)^T.

🚀 JEE Advanced Edge

Using Cayley-Hamilton to find high powers or the inverse without direct computation: For a 2×2 matrix A satisfying A²-(trace A)A+(det A)I=0, this single relation lets you express A² (and by repeated substitution, any higher power Aⁿ) as a combination of A and I — far faster than direct repeated matrix multiplication. Multiplying the same relation through by A⁻¹ also gives A⁻¹ directly in terms of A and I when det A≠0, without computing the adjoint matrix at all.

Why every skew-symmetric matrix of odd order has determinant 0: For a skew-symmetric matrix A (Aᵗ=-A) of order n, det(A)=det(Aᵗ)=det(-A)=(-1)ⁿdet(A). If n is ODD, (-1)ⁿ=-1, giving det(A)=-det(A), which forces det(A)=0 — a property that resolves "find the determinant" questions instantly without expanding anything, purely from the matrix's odd order and skew-symmetry.

Worked problem: For A=[[1,2],[2,1]], verify the Cayley-Hamilton theorem and use it to find A⁻¹. Approach: trace(A)=1+1=2, det(A)=1×1-2×2=1-4=-3. Characteristic equation: A²-2A-3I=0, so A²=2A+3I. Rearranging for inverse: from A²-2A-3I=0, divide by A (multiply by A⁻¹): A-2I-3A⁻¹=0, so A⁻¹=(A-2I)/3 = [[1-2,2],[2,1-2]]/3 = [[-1,2],[2,-1]]/3.

Worked Example: Evaluating a 3×3 Determinant

Evaluate det([[1,2,3],[4,5,6],[7,8,9]]).

Expand along Row 1: det = 1·det([[5,6],[8,9]]) − 2·det([[4,6],[7,9]]) + 3·det([[4,5],[7,8]]).

= 1·(45−48) − 2·(36−42) + 3·(32−35) = 1·(−3) − 2·(−6) + 3·(−3) = −3 + 12 − 9 = 0. A determinant of 0 means the matrix is singular (no inverse). Here, each row is an AP with common difference 3, so the rows are linearly dependent.

Worked Example: Solving a System Using Cramer's Rule

Solve 2x + y = 5, x − y = 1 using Cramer's rule.

D = det([[2,1],[1,-1]]) = −2−1 = −3. Dx = det([[5,1],[1,-1]]) = −5−1 = −6. Dy = det([[2,5],[1,1]]) = 2−5 = −3.

x = Dx/D = −6/−3 = 2, y = Dy/D = −3/−3 = 1. Cramer's rule: replace each column of D with the constant column to get the respective numerator determinant.

2 Revise ~2 min before the exam

📐 Formula Sheet

  • Order: an m × n matrix has m rows and n columns; A + B needs identical orders
  • Multiplication: AB is defined only when columns of A = rows of B; (m×n)(n×p) = m×p
  • Not commutative: AB ≠ BA in general  |  but (AB)C = A(BC) always
  • Transpose: (Aᵀ)ᵀ = A  |  (AB)ᵀ = BᵀAᵀ  |  (A + B)ᵀ = Aᵀ + Bᵀ
  • Symmetric: Aᵀ = A  |  Skew-symmetric: Aᵀ = −A (all diagonal entries are 0)
  • Any square matrix splits: A = ½(A + Aᵀ) + ½(A − Aᵀ) = symmetric + skew-symmetric
  • Inverse: A⁻¹ = adj(A)/|A|, exists only if |A| ≠ 0  |  (AB)⁻¹ = B⁻¹A⁻¹
  • Orthogonal: AAᵀ = I  |  Idempotent: A² = A  |  Nilpotent: Aᵏ = 0
3 Practice apply it

✍️ Worked Examples

Example 1 — Matrix multiplication
Q: Find AB where A = [1 2; 3 4] and B = [5 6; 7 8].
Step 1 — Each entry is a row of A dotted with a column of B.
Step 2 — Top row: (1)(5) + (2)(7) = 19; (1)(6) + (2)(8) = 22.
Step 3 — Bottom row: (3)(5) + (4)(7) = 43; (3)(6) + (4)(8) = 50.
Answer: AB = [19 22; 43 50]. Note: BA = [23 34; 31 46] — different, confirming that matrix multiplication does not commute.

Example 2 — Inverse of a 2×2 matrix
Q: Find the inverse of A = [2 1; 5 3].
Step 1 — Determinant: |A| = (2)(3) − (1)(5) = 1. Non-zero, so the inverse exists.
Step 2 — For a 2×2, adj(A) swaps the diagonal and negates the off-diagonal: adj(A) = [3 −1; −5 2].
Step 3 — Divide by the determinant: A⁻¹ = [3 −1; −5 2]/1.
Answer: A⁻¹ = [3 −1; −5 2]. Check: AA⁻¹ = [1 0; 0 1] ✓.

Example 3 — Splitting into symmetric and skew parts
Q: Express A = [1 3; 5 7] as the sum of a symmetric and a skew-symmetric matrix.
Step 1 — Transpose: Aᵀ = [1 5; 3 7].
Step 2 — Symmetric part: ½(A + Aᵀ) = ½[2 8; 8 14] = [1 4; 4 7].
Step 3 — Skew part: ½(A − Aᵀ) = ½[0 −2; 2 0] = [0 −1; 1 0].
Answer: A = [1 4; 4 7] + [0 −1; 1 0]. Check: the first equals its own transpose; the second equals its negative ✓.

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Frequently Asked Questions — Matrices

What are the key concepts in Matrices?
Matrix operations, determinants, inverses, and solving linear systems
Is Matrices important for JEE?
Yes. Matrices is part of the Mathematics Class 12 NCERT syllabus and is directly tested in JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Matrices questions on StudyHub?
Open StudyHub and select Mathematics → Matrices. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at JEE level with full step-by-step explanations.

References

  1. NCERT Class 12 Mathematics Textbook — Chapter: Matrices
  2. CBSE Curriculum — Mathematics (Class 12)
  3. NTA JEE Main Official Syllabus — subject-wise topic list