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Mechanical Properties of Solids

Stress, strain, Hookes law, and the elastic moduli that describe how solids deform and recover under load.

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Reading time~7 min
Revision time~2 min
Last updated2026-07-19
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🎯 Key Points

  • Stress = F/A (Pa); Strain = fractional deformation (dimensionless); Hooke's Law: stress = modulus × strain (within elastic limit)
  • Young's modulus Y = longitudinal stress/strain (tension/compression); Shear modulus G = shear stress/strain; Bulk modulus B = −ΔP/(ΔV/V)
  • Stress-strain curve order: proportional limit → elastic limit → yield point → ultimate tensile strength → fracture
  • Poisson's ratio σ = lateral strain/longitudinal strain, typically 0.2–0.4
  • Elastic PE per unit volume = ½Y(strain)² — used in bow-and-arrow, spring, and wire-stretching energy problems
Stress-Strain Curve for a Ductile Metal WireStrainStresselastic limityield pointUTS (max stress)fractureSlope of the straight (elastic) portion = Young's modulus Y; the curve beyond elastic limit shows permanent (plastic) deformation

A typical stress-strain curve: the initial straight line (Hooke's Law region, slope = Young's modulus) ends at the elastic limit; beyond the yield point, deformation becomes permanent, peaking at the ultimate tensile strength before the wire finally fractures.

Stress and Strain

  • Stress is the restoring force per unit area developed inside a deformed body: stress = F/A, SI unit N/m² (pascal, Pa)
  • Strain is the fractional change produced in a body due to deforming force; it is dimensionless (a ratio)
  • Longitudinal strain = change in length / original length (ΔL/L)
  • Shearing strain = relative displacement / perpendicular distance = tan(θ) ≈ θ (for small angles)
  • Volumetric strain = change in volume / original volume (ΔV/V)

Types of Stress

  • Longitudinal (tensile/compressive) stress: force is perpendicular to the cross-section, causing elongation or compression along the length
  • Shearing stress: force is tangential to the surface, causing a change in shape without a change in volume
  • Hydraulic/volumetric stress: a uniform force per unit area acting normally over the entire surface, causing a change in volume only

Hookes Law and the Stress-Strain Curve

  • Hookes law: within the elastic limit, stress is directly proportional to strain, i.e. stress = (modulus) × strain
  • Proportional limit: the point up to which stress-strain graph is a straight line
  • Elastic limit: the maximum stress beyond which the body does not return to its original shape on removing the load
  • Yield point: beyond this, strain increases rapidly even for small increase in stress (plastic deformation begins)
  • Ultimate tensile strength: maximum stress the material can withstand before necking
  • Fracture point: the point at which the material breaks
  • Ductile materials (like copper) show a large plastic region; brittle materials (like glass) fracture soon after the elastic limit
Stress-strain curve for a ductile material showing the linear region, yield strength, ultimate strength, strain-hardening and necking regions, and the fracture point

Stress−strain curve of a ductile material. The initial straight-line slope is Young's modulus; beyond the yield strength it deforms plastically up to the ultimate strength, then necks and fractures. Image: Breakdown, CC BY-SA 3.0, via Wikimedia Commons.

The Three Elastic Moduli

  • Youngs modulus (Y): Y = longitudinal stress / longitudinal strain = (F/A)/(ΔL/L), applies to solids under tension/compression
  • Shear modulus / modulus of rigidity (G or η): G = shearing stress / shearing strain = (F/A)/θ; for a given material G is usually less than Y
  • Bulk modulus (B or K): B = -ΔP / (ΔV/V) (negative sign shows volume decreases as pressure increases); compressibility = 1/B
  • Gases have very small bulk modulus (highly compressible) compared to solids and liquids
  • Steel is more elastic than rubber for the same stress because steel undergoes a smaller strain (higher Y)

Poissons Ratio

  • When a rod is stretched, it elongates but also contracts laterally; Poissons ratio σ = lateral strain / longitudinal strain
  • σ is dimensionless and theoretically lies between -1 and 0.5 for most materials; typical values are 0.2 to 0.4

Elastic Potential Energy in a Stretched Wire

  • Work done in stretching a wire is stored as elastic potential energy: U = ½ × stress × strain × volume = ½ F·ΔL
  • Elastic potential energy per unit volume = ½ × Y × (strain)²

Applications

  • Bridge girders and cantilever beams are designed using depression formulas; using an I-shaped cross-section gives high strength without too much extra material
  • Metallic ropes/cables used in cranes and bridges are chosen for high Youngs modulus so they do not stretch excessively under heavy load
  • Thicker columns and pillars in buildings reduce stress (force/area) so the structure stays within its elastic limit
  • Rubber is used in shock absorbers and vibration mounts because it can sustain large strains without crossing its elastic limit

Relations Between the Elastic Moduli

  • The three moduli and Poisson's ratio (σ) are interrelated for an isotropic material:
  • Y = 2G(1 + σ) — links Young's modulus and shear modulus
  • Y = 3B(1 − 2σ) — links Young's modulus and bulk modulus
  • Y = 9BG/(3B + G) — combined relation
  • These show only two of the four quantities (Y, B, G, σ) are independent

Elastic Behaviour: Fatigue and After-effect

  • Elastic after-effect: the delay in a body returning fully to its original state after the deforming force is removed (negligible in quartz, large in glass)
  • Elastic fatigue: the loss of strength of a material caused by repeated cycles of stress; a wire subjected to repeated stretching can break below its normal breaking stress
  • Elastic hysteresis: for materials like rubber, the loading and unloading stress–strain curves do not coincide; the enclosed area represents energy dissipated as heat per cycle

Thermal Stress and Factor of Safety

  • Thermal stress: when a rod is heated but not allowed to expand, it develops stress = Y·α·ΔT (α = coefficient of linear expansion, ΔT = temperature change)
  • This is why gaps are left in railway tracks and bridges to allow for thermal expansion
  • Breaking stress: the maximum stress a material can bear before rupture; it depends on the material, not on the wire's dimensions
  • Factor of safety = breaking stress / working (permitted) stress; engineers keep working loads well below the breaking limit for safe design

🚀 JEE Advanced Edge

Elongation under self-weight and variable load: For a wire/rod hanging under its own weight, the tension (and hence stress) varies along its length, so total elongation requires integrating dL = (F(x)/AY)dx over the length, rather than just applying ΔL=FL/AY with a single F.

Series/parallel combination of wires: Two wires of different Y joined end-to-end (series) under the same load stretch by amounts inversely proportional to their individual AY/L "stiffness"; wires side-by-side sharing a load (parallel) split the load in proportion to their stiffness.

Worked problem: A wire of length 2 m and cross-section area 1 mm² stretches by 0.1 mm under a load of 20 N. Find Young's modulus. Approach: Y = (F/A)/(ΔL/L) = (20/10⁻⁶)/(0.1×10⁻³/2) = (2×10⁷)/(5×10⁻⁵) = 4×10¹¹ Pa.

2 Revise ~2 min before the exam

📐 Formula Sheet

  • Stress: σ = F/A (unit: pascal)  |  Strain: ε = ΔL/L (dimensionless)
  • Hooke's law: stress ∝ strain within the elastic limit
  • Young's modulus: Y = stress/strain = FL/(AΔL)
  • Bulk modulus: B = −P/(ΔV/V)  |  Compressibility: K = 1/B
  • Shear (rigidity) modulus: η = shear stress/shear strain = F/(Aθ)
  • Poisson's ratio: ν = lateral strain/longitudinal strain (typically 0.2–0.5)
  • Elastic PE: U = ½ × stress × strain × volume = ½FΔL
  • Energy density: u = ½ × stress × strain = ½Yε²
3 Practice apply it

✍️ Worked Examples

Example 1 — Extension of a wire
Q: A 2 m steel wire of cross-section 1 mm² carries a 100 N load. Find its extension. (Y = 2 × 10¹¹ Pa)
Step 1 — Convert area: 1 mm² = 10⁻⁶ m².
Step 2 — Rearrange Y = FL/(AΔL): ΔL = FL/(AY).
Step 3 — Substitute: ΔL = (100 × 2)/(10⁻⁶ × 2 × 10¹¹) = 200/(2 × 10⁵) = 10⁻³ m.
Answer: 1 mm. Trap: mm² → m² is a factor of 10⁻⁶, not 10⁻³.

Example 2 — Comparing two wires
Q: Two wires of the same material and length, with radii r and 2r, carry the same load. Compare their extensions.
Step 1 — ΔL = FL/(AY), so at fixed F, L and Y, ΔL ∝ 1/A.
Step 2 — Area scales as r²: the thicker wire has 4× the area.
Step 3 — So its extension is one quarter.
Answer: the thicker wire stretches 4× less. Note: doubling the radius quadruples the load-bearing capacity for the same strain.

Example 3 — Elastic energy stored
Q: A wire stretches 2 mm under a 50 N load. Find the elastic potential energy stored.
Step 1 — Use U = ½FΔL (the ½ appears because the force grows from 0 to F as it stretches).
Step 2 — Convert: ΔL = 2 mm = 2 × 10⁻³ m.
Step 3 — Compute: U = ½ × 50 × 2 × 10⁻³ = 0.05 J.
Answer: 0.05 J. Trap: writing U = FΔL forgets the ½ and doubles the answer.

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Frequently Asked Questions — Mechanical Properties of Solids

What are the key concepts in Mechanical Properties of Solids?
Stress, strain, Hookes law, and the elastic moduli that describe how solids deform and recover under load.
Is Mechanical Properties of Solids important for NEET & JEE?
Yes. Mechanical Properties of Solids is part of the Physics Class 11 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Mechanical Properties of Solids questions on StudyHub?
Open StudyHub and select Physics → Mechanical Properties of Solids. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at NEET & JEE level with full step-by-step explanations.

References

  1. NCERT Class 11 Physics Textbook — Chapter: Mechanical Properties of Solids
  2. CBSE Curriculum — Physics (Class 11)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list