📚 StudyHub

🧪 Chemistry  ·  Class 12  ·  NEET & JEE

Amines

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

Practice Amines Quiz — 100% Free →
Reading time~8 min
Revision time~3 min
Last updated2026-07-19
1 Read the chapter ~8 min

🎯 Key Points

  • Aqueous basicity (aliphatic): 2° > 1° > 3° > NH₃ (solvation effects dominate); gas phase: 3° > 2° > 1° > NH₃ (pure +I effect)
  • Aniline is a much weaker base than aliphatic amines — its N lone pair delocalises into the benzene ring
  • HNO₂ test: 1° aliphatic amine → N₂ gas; 1° aromatic amine → stable diazonium salt (0-5°C); 2° amine → N-nitroso oil; 3° amine → no reaction
  • Gabriel synthesis gives pure 1° amines only (no aryl amines possible); Hofmann bromamide degradation shortens the chain by one carbon
  • Diazonium salt is a versatile synthetic intermediate: → phenol, → benzene (with H₃PO₂), → azo dyes (coupling with phenol/aniline)
Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton — which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Classification of Amines

  • Primary (1°): One alkyl or aryl group on N (R-NH₂); e.g., methylamine CH₃NH₂
  • Secondary (2°): Two groups on N (R₂NH); e.g., dimethylamine
  • Tertiary (3°): Three groups on N (R₃N); e.g., trimethylamine

Basicity of Amines

  • Amines are Lewis and Brønsted bases (lone pair on N)
  • Aliphatic amines: 2° > 1° > 3° > NH₃ (in aqueous solution due to solvation effects)
  • Aromatic amines (aniline) are much weaker bases than aliphatic amines (lone pair delocalised into ring)
  • Electron-donating groups on ring increase basicity of arylamines; -NO₂ decreases it

Important Reactions

  • Reaction with nitrous acid (HNO₂):
    • 1° aliphatic amine: unstable diazonium salt → N₂ gas
    • 1° aromatic amine: stable diazonium salt (ArN₂⁺Cl⁻) at 0-5°C
    • 2° amine: N-nitroso compound (yellow oil)
    • 3° amine: no visible reaction
  • Coupling reaction: Diazonium salt + phenol or aniline → azo dye (orange or red colour)
  • Hofmann's bromamide degradation: RCONH₂ + Br₂/KOH → RNH₂ (one carbon less)

Preparation

  • Reduction of nitro compounds: ArNO₂ + Fe/HCl → ArNH₂
  • Gabriel phthalimide synthesis: gives only 1° amines
  • Reductive amination of carbonyl with NH₃ and H₂

More Preparation Methods

  • Gabriel phthalimide synthesis: Phthalimide + KOH gives potassium salt, which is alkylated with RX, then hydrolysed to give a pure 1° amine (avoids over-alkylation); cannot be used to prepare aromatic amines since aryl halides do not undergo SN2 easily
  • Ammonolysis of alkyl halides: RX + excess NH₃ → RNH₂ (tends to give a mixture of 1°, 2°, 3° amines and quaternary salt)
  • Reduction of nitriles: RCN + H₂/Ni or LiAlH₄ → RCH₂NH₂
  • Hoffmann bromamide degradation mechanism: Amide reacts with Br₂/KOH to form an isocyanate intermediate via nitrene, which hydrolyses to the amine, the product has one carbon less than the starting amide

Basicity Order Explained

  • In the gas phase (no solvation), basicity order is 3° > 2° > 1° > NH₃, purely due to the +I effect of alkyl groups increasing electron density on N
  • In aqueous solution, the order changes to 2° > 1° > 3° > NH₃ because 3° amines have fewer N-H bonds for hydrogen bonding with water, reducing solvation stabilisation of the resulting cation
  • Ethylamine (pKb about 3.3) is a stronger base than aniline (pKb about 9.4) because the lone pair on aniline's N is delocalised into the benzene ring, making it less available for protonation

Diazonium Salt Reactions

  • Replacement by -OH: ArN₂⁺ + H₂O (warm) → ArOH + N₂
  • Replacement by -Cl, -Br: with corresponding Cu(I) halide (Sandmeyer reaction)
  • Replacement by -CN: ArN₂⁺ + CuCN → ArCN + N₂ (Sandmeyer-type, used to extend carbon chain)
  • Replacement by -F: via Balz-Schiemann reaction (using HBF₄)
  • Reduction to ArH: ArN₂⁺ + H₃PO₂/H₂O → ArH + N₂ (removes the amino group entirely)
  • Coupling with phenol/aniline: gives brightly coloured azo dyes used in the dye and textile industry
Structure of benzenediazonium chloride: a benzene ring bonded to an N triple bond N group carrying a positive charge, with a chloride counter-ion.

Benzenediazonium chloride (C6H5N2+ Cl) forms when aniline is treated with nitrous acid (NaNO2 + HCl) at 0–5°C. Its −N2+ group is an excellent leaving group, making these salts key intermediates for making phenols, haloarenes and azo dyes. Image: Benjah-bmm27, Public Domain, via Wikimedia Commons.

Structure and Nomenclature of Amines

  • Nitrogen in amines is sp³ hybridised with a lone pair, giving a pyramidal shape (like ammonia); the bond angles are close to 108°
  • Common names: alkyl groups named alphabetically followed by "amine" (e.g. ethylmethylamine); C₆H₅NH₂ is aniline
  • IUPAC names: alkanamine — the terminal -e of the alkane is replaced by -amine (methanamine for CH₃NH₂, ethanamine for C₂H₅NH₂)
  • In secondary and tertiary amines the other groups on nitrogen take the locant "N-" (e.g. N-methylethanamine, N,N-dimethylmethanamine)

Distinguishing Tests: Hinsberg and Carbylamine

  • Carbylamine (isocyanide) test: only 1° amines, on warming with CHCl₃ and alcoholic KOH, give foul-smelling isocyanides — RNH₂ + CHCl₃ + 3KOH → RNC + 3KCl + 3H₂O; 2° and 3° amines give no reaction, so it is a test for 1° amines
  • Hinsberg's test: amines are shaken with benzenesulphonyl chloride (C₆H₅SO₂Cl). A 1° amine gives a product soluble in KOH (its remaining N-H is acidic); a 2° amine gives a product insoluble in KOH; a 3° amine does not react — distinguishing all three classes

Other Chemical Reactions of Amines

  • Alkylation: amines react with alkyl halides to give successively 2° and 3° amines and finally a quaternary ammonium salt
  • Acylation: 1° and 2° amines react with acid chlorides or anhydrides to give substituted amides (e.g. aniline + acetyl chloride → acetanilide); acetylation lowers the reactivity of the amino group
  • Electrophilic substitution in aromatic amines: -NH₂ is a strong activating ortho/para director, so aniline + bromine water instantly gives 2,4,6-tribromoaniline (white precipitate)
  • To limit substitution to one position (mono-bromination or nitration), the amine is first acetylated to acetanilide, which also protects it from oxidation by the acidic reaction mixture and favours the para product

🚀 JEE Advanced Edge

Why diazonium salts are unstable above 5°C: The N≡N⁺ group is a good leaving group, and the salt readily decomposes to release N₂ gas and form a highly reactive aryl cation/free radical, especially as thermal energy increases — this instability is exactly why diazonium chemistry must be carried out cold, and why it's so useful synthetically (the N₂ leaving group can be replaced by almost anything: -OH, -CN, -X, -H).

Why aniline doesn't undergo Friedel-Crafts reactions: AlCl₃ (the Lewis acid catalyst) coordinates with aniline's lone pair on nitrogen, forming a salt that makes the ring strongly electron-withdrawing (deactivated) instead of activated — this self-poisoning of the catalyst is why aniline must first be protected (e.g., by acetylation to acetanilide) before any Friedel-Crafts-type reaction can be attempted.

Worked problem: Rank the basicity of ammonia, methylamine, and aniline. Approach: Aniline < ammonia < methylamine. Methylamine's alkyl group donates electron density (+I), increasing N's availability to accept a proton, making it MORE basic than plain ammonia. Aniline's lone pair is delocalised into the ring (resonance), making it LESS available than even ammonia's lone pair — resonance delocalisation has a much bigger basicity-reducing effect than the inductive effect's basicity-increasing effect.

2 Revise ~3 min before the exam

🔑 Key Reactions

  • Basicity: amines are basic (lone pair on N); in water 2° > 1° > 3° for aliphatic amines (solvation + steric balance)
  • Aromatic amines are weaker bases than aliphatic (the lone pair delocalises into the ring)
  • Preparation: reduction of nitro compounds, nitriles or amides; Gabriel synthesis (pure 1° amines); Hofmann bromamide (one carbon shorter)
  • Carbylamine test: 1° amine + CHCl₃ + KOH → foul-smelling isocyanide (test for 1° amines only)
  • Hinsberg's test: distinguishes 1°, 2° and 3° amines using benzenesulfonyl chloride
  • Diazotisation: aromatic 1° amine + HNO₂ (0–5°C) → diazonium salt
  • Coupling: diazonium salt + phenol/amine → azo dye (coloured)
3 Practice apply it

✍️ Worked Examples

Example 1 — Why aniline is a weaker base than methylamine
Q: Explain why aniline (C₆H₅NH₂) is less basic than methylamine (CH₃NH₂).
Step 1 — Basicity depends on the availability of nitrogen's lone pair to accept a proton.
Step 2 — In aniline the lone pair is delocalised into the benzene ring by resonance, so it is less available.
Step 3 — In methylamine the +I effect of the methyl group pushes electron density onto N, making the lone pair more available.
Answer: aniline's lone pair is tied up in ring resonance, so it is the weaker base. Key idea: anything that delocalises the N lone pair reduces basicity.

Example 2 — Identifying a primary amine
Q: Which test uniquely identifies a primary amine, and what is observed?
Step 1 — Use the carbylamine (isocyanide) test: warm the amine with chloroform and alcoholic KOH.
Step 2 — Only primary amines react, forming an isocyanide (carbylamine).
Step 3 — The product has an extremely offensive smell.
Answer: the carbylamine test — a foul odour confirms a primary amine. Note: secondary and tertiary amines give no such smell.

Example 3 — Diazonium chemistry
Q: Why must aniline be diazotised at 0–5°C?
Step 1 — Aniline reacts with nitrous acid to form benzenediazonium chloride.
Step 2 — The diazonium salt is thermally unstable and decomposes above ~5°C, releasing N₂ and forming phenol.
Step 3 — Keeping it cold preserves the salt for later coupling or substitution.
Answer: low temperature stops the unstable diazonium salt from decomposing. Note: these salts are the gateway to azo dyes and many aromatic substitutions.

Practice Amines Quiz — 100% Free →

Frequently Asked Questions — Amines

What are the key concepts in Amines?
Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.
Is Amines important for NEET & JEE?
Yes. Amines is part of the Chemistry Class 12 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Amines questions on StudyHub?
Open StudyHub and select Chemistry → Amines. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at NEET & JEE level with full step-by-step explanations.

References

  1. NCERT Class 12 Chemistry Textbook — Chapter: Amines
  2. CBSE Curriculum — Chemistry (Class 12)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list