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Electromagnetic Waves

Maxwell's equations, EM spectrum, properties, and applications of each band.

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Reading time~6 min
Revision time~2 min
Last updated2026-07-19
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🎯 Key Points

  • c=1/√(μ₀ε₀)=3×10⁸ m/s; E, B, and propagation direction are mutually perpendicular; E₀/B₀=c
  • Displacement current I_d=ε₀(dΦ_E/dt) — Maxwell's fix that makes Ampere's law work even where there's no actual charge flow (e.g. between capacitor plates)
  • EM spectrum (increasing frequency/energy): Radio < Microwave < Infrared < Visible < UV < X-ray < Gamma ray
  • Radiation pressure = I/c; intensity I=½ε₀cE₀²
  • Energy is shared EQUALLY between electric and magnetic fields on time-average in an EM wave
Electromagnetic Wave: E ⊥ B ⊥ Direction of TravelpropagationE (electric field, vertical plane)B (magnetic field, horizontal plane, perpendicular to E)

In an electromagnetic wave, the oscillating electric field (E) and magnetic field (B) are perpendicular to each other and to the direction the wave travels — a purely transverse wave that needs no medium, unlike sound.

Maxwell's Equations (Concept)

  • Gauss's law for E: electric flux from charge
  • Gauss's law for B: no magnetic monopoles (magnetic flux always zero)
  • Faraday's law: changing B creates E
  • Ampere-Maxwell law: changing E creates B (displacement current)
  • Displacement current: I_d = ε₀ × dΦ_E/dt (fills gap between capacitor plates)

Properties of EM Waves

  • Speed in vacuum: c = 1/√(μ₀ε₀) = 3 × 10⁸ m/s
  • E, B, and propagation direction are mutually perpendicular
  • E₀/B₀ = c (ratio of field amplitudes)
  • Transverse waves; can travel in vacuum
  • Carry energy and momentum: pressure = I/c (intensity/speed)

Electromagnetic Spectrum

  • Radio waves (> 0.1 m): radio, TV, MRI
  • Microwaves (1 mm - 0.1 m): microwave ovens, radar, satellite
  • Infrared (700 nm - 1 mm): thermal imaging, remote controls, heating
  • Visible (400-700 nm): VIBGYOR (violet to red)
  • Ultraviolet (10-400 nm): sterilization, vitamin D synthesis, skin cancer
  • X-rays (0.01-10 nm): medical imaging, crystallography
  • Gamma rays (< 0.01 nm): cancer treatment, nuclear reactions
The electromagnetic spectrum from radio through microwave, infrared, visible, ultraviolet, X-ray to gamma ray, showing wavelength in metres, an object of comparable size for each band from buildings down to atomic nuclei, frequency in hertz, and whether each band penetrates Earth atmosphere

The electromagnetic spectrum: all bands travel at c, with wavelength falling and frequency (and photon energy) rising from radio to gamma rays. Image: Inductiveload, NASA, CC BY-SA 3.0, via Wikimedia Commons.

Applications

  • Radio: AM (amplitude modulation), FM (frequency modulation)
  • Microwaves: heating water molecules (dielectric heating)
  • X-rays: discovered by Roentgen; Bragg diffraction for crystal structure

Displacement Current in Detail

  • Displacement current arises from a changing electric field (not actual charge flow) and was introduced by Maxwell to make Ampere's law consistent with charge conservation in situations like a charging capacitor
  • Total current (conduction + displacement) is continuous across any circuit, including the gap between capacitor plates
  • Modified Ampere-Maxwell law: ∮B·dl = μ₀(I_c + I_d)

Energy in EM Waves

  • EM waves carry energy equally shared between electric and magnetic fields on time-average
  • Average energy density: u_avg = ½ε₀E₀² (electric) + B₀²/2μ₀ (magnetic), each contributing equally
  • Intensity (average power per unit area): I = ½ε₀cE₀²

Sources of EM Waves by Band

  • Radio and microwaves: produced by oscillating currents in electronic circuits and antennas
  • Infrared: produced by hot bodies and molecular vibrations
  • Visible and ultraviolet: produced by electronic transitions in atoms
  • X-rays: produced by sudden deceleration of high-energy electrons striking a target (bremsstrahlung) or inner-shell electron transitions
  • Gamma rays: produced by nuclear transitions and radioactive decay

Nature and Mathematical Description of EM Waves

  • For a wave travelling along x, the fields vary as E = E₀ sin(kx − ωt) along one transverse axis (say y) and B = B₀ sin(kx − ωt) along the perpendicular axis (z) — E and B oscillate in phase, reaching their maxima and zeros together
  • The wave number k = 2π/λ and angular frequency ω = 2πf are linked by the wave speed ω/k = c = fλ
  • EM waves are purely transverse (E and B both perpendicular to the propagation direction) and, unlike mechanical waves, require no material medium — they travel through vacuum
  • An accelerating (or oscillating) electric charge is the fundamental source of an electromagnetic wave, radiating at the frequency of its oscillation

Speed of EM Waves in a Material Medium

  • In a medium of permeability μ and permittivity ε, the wave speed is v = 1/√(με), which is always less than the vacuum speed c = 1/√(μ₀ε₀)
  • The refractive index is n = c/v = √(μ_r ε_r); for most transparent non-magnetic media μ_r ≈ 1, so n ≈ √ε_r
  • When an EM wave enters a medium its frequency stays fixed (set by the source) while its speed and wavelength both decrease by the factor n

🚀 JEE Advanced Edge

Radiation pressure — absorption vs reflection: A surface that fully ABSORBS incident EM radiation experiences pressure P=I/c; a surface that fully REFLECTS it experiences DOUBLE the pressure, P=2I/c, since the wave's momentum is reversed rather than just absorbed (analogous to elastic vs inelastic collision momentum transfer).

Calculating fields from intensity: Since I=½ε₀cE₀², given a known intensity (e.g. solar constant ≈1400 W/m² at Earth) you can solve for E₀=√(2I/ε₀c), and then B₀=E₀/c — a common way numericals connect EM wave energy to field amplitudes.

Worked problem: Sunlight has an intensity of 1400 W/m² at Earth's surface. Find the radiation pressure on a perfectly absorbing surface, and compare it to a perfectly reflecting one. Approach: P_absorb=I/c=1400/(3×10⁸)≈4.67×10⁻⁶ Pa. P_reflect=2I/c≈9.33×10⁻⁶ Pa — twice as much.

2Revise~2 min before the exam

📐 Formula Sheet

  • Speed in vacuum: c = 1/√(μ₀ε₀) = 3 × 10⁸ m/s  |  in a medium: v = 1/√(με) = c/n
  • Field relation: E₀/B₀ = c  |  E, B and the direction of travel are mutually perpendicular
  • Displacement current: Id = ε₀·dΦE/dt (Maxwell's addition to Ampère's law)
  • Energy density: u = ½ε₀E² + B²/2μ₀; both halves contribute equally
  • Intensity: I = ½ε₀E₀²c  |  Poynting vector: S = (E × B)/μ₀
  • Radiation pressure: P = I/c (absorbed) or 2I/c (fully reflected)
  • Spectrum in order of increasing frequency: radio → microwave → infrared → visible → ultraviolet → X-ray → gamma
  • Visible range: ≈ 400 nm (violet) to 700 nm (red)
3Practiceapply it

✍️ Worked Examples

Example 1 — Finding B from E
Q: An electromagnetic wave has a peak electric field of 6 V/m. Find its peak magnetic field.
Step 1 — Use E₀/B₀ = c.
Step 2 — Rearrange: B₀ = E₀/c = 6/(3 × 10⁸).
Step 3 — Compute: B₀ = 2 × 10⁻⁸ T.
Answer: 2 × 10⁻⁸ T. Note: B always looks tiny next to E in SI units, but both carry equal energy — the units simply differ by a factor of c.

Example 2 — Wavelength from frequency
Q: An FM station broadcasts at 100 MHz. Find its wavelength.
Step 1 — Use c = fλ.
Step 2 — Rearrange: λ = c/f = (3 × 10⁸)/(100 × 10⁶).
Step 3 — Compute: λ = 3 m.
Answer: 3 m. Note: antennas are typically built around a quarter or half of the wavelength, which is why FM aerials are around a metre long.

Example 3 — Radiation pressure
Q: Sunlight of intensity 1400 W/m² falls on a perfectly reflecting surface. Find the radiation pressure.
Step 1 — For full reflection: P = 2I/c (the photons reverse, so momentum change doubles).
Step 2 — Substitute: P = (2 × 1400)/(3 × 10⁸).
Step 3 — Compute: P ≈ 9.3 × 10⁻⁶ Pa.
Answer: ≈ 9.3 μPa. Note: tiny, but enough to drive solar sails over long durations — and it is why comet tails point away from the Sun.

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Frequently Asked Questions — Electromagnetic Waves

What are the key concepts in Electromagnetic Waves?
Maxwell's equations, EM spectrum, properties, and applications of each band.
Is Electromagnetic Waves important for NEET & JEE?
Yes. Electromagnetic Waves is part of the Physics Class 12 NCERT syllabus and is directly tested in NEET and JEE examinations. StudyHub provides structured notes, diagrams, and practice questions covering all exam-level subtopics.
How can I practice Electromagnetic Waves questions on StudyHub?
Open StudyHub and select Physics → Electromagnetic Waves. Choose Easy, Medium, or Hard difficulty. Hard-tier questions are at NEET & JEE level with full step-by-step explanations.

References

  1. NCERT Class 12 Physics Textbook — Chapter: Electromagnetic Waves
  2. CBSE Curriculum — Physics (Class 12)
  3. NTA NEET UG Official Syllabus — subject-wise topic list
  4. NTA JEE Main Official Syllabus — subject-wise topic list